If x men working x hours per day can do x units of work in x days, then y men working y hours per day in y days would be able to do k units of work. What is the value of k?
y 3x -2
This problem involves calculating the amount of work done based on the number of workers, the hours they work, and the duration. We are given a scenario with 'x' workers and asked to find the work done ('k') under different conditions with 'y' workers. The key is to understand the relationship between the amount of work done and the factors involved.
The total amount of work done is directly proportional to the number of men working, the number of hours they work each day, and the number of days they work. We can express this relationship using the following formula:
\[ \frac{W_1}{M_1 \times H_1 \times D_1} = \frac{W_2}{M_2 \times H_2 \times D_2} \]Where:
Let's identify the values from the problem:
Now, we plug these values into the formula:
\[ \frac{x}{x \times x \times x} = \frac{k}{y \times y \times y} \]Simplify the denominators:
\[ \frac{x}{x^3} = \frac{k}{y^3} \]Using exponent rules (\( \frac{a^m}{a^n} = a^{m-n} \)), we can simplify the left side:
\[ x^{1-3} = \frac{k}{y^3} \] \[ x^{-2} = \frac{k}{y^3} \]To find the value of \(k\), we need to isolate it. Multiply both sides of the equation by \(y^3\):
\[ k = y^3 \times x^{-2} \]This can also be written as:
\[ k = \frac{y^3}{x^2} \]Therefore, the value of \(k\), representing the units of work done by \(y\) men working \(y\) hours per day in \(y\) days, is \(y^3 x^{-2}\). This matches the fourth option provided.
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