We are given the relationship between three quantities a, b, and c as:
$ \text{a} : 3 = \text{b} : 7 = \text{c} : 9 $
This can be rewritten in fractional form:
$ \frac{\text{a}}{3} = \frac{\text{b}}{7} = \frac{\text{c}}{9} $
Let's introduce a constant of proportionality, $k$.
$ \frac{\text{a}}{3} = k \quad \Rightarrow \quad \text{a} = 3k $
$ \frac{\text{b}}{7} = k \quad \Rightarrow \quad \text{b} = 7k $
$ \frac{\text{c}}{9} = k \quad \Rightarrow \quad \text{c} = 9k $
We need to find the value of the expression $\frac{\text{a}+\text{b}+\text{c}}{\text{a}}$.
First, find the sum $\text{a}+\text{b}+\text{c}$ in terms of $k$:
$ \text{a}+\text{b}+\text{c} = 3k + 7k + 9k = 19k $
Now substitute the values of $\text{a}+\text{b}+\text{c}$ and $\text{a}$ into the expression:
$ \frac{\text{a}+\text{b}+\text{c}}{\text{a}} = \frac{19k}{3k} $
Assuming $k \neq 0$, we can cancel $k$ from the numerator and the denominator:
$ \frac{19k}{3k} = \frac{19}{3} $
Therefore, the value of the expression is $\frac{19}{3}$.
In a mixture of 156 litres, the ratio of milk and water is 7 : 6. How much water should be added to make the ratio 14 : 13?
If the ratio of the first to second number is 3 : 4 and that of the second to the third number is 8 : 5, and sum of three numbers is 190 then the third number is:
The third proportional to 9 and 15 is:
The average age of 3 persons is 30 years.If their ages are in the ratio of 3 : 5 : 7 respectively, then the age of the eldest person is:
The income of A and B are in the ratio 5 : 3. The expenses of A, B and C are in the ratio of 8 : 5 : 2. If C spends 2000 and B saves ₹ 700, then A saves: