This solution explains how to find the electric Current (I) when Power (P) and Resistance (R) are given.
The relationship between Power ($P$), Current ($I$), and Resistance ($R$) is given by the formula:
$ P = I^2 \times R $
To find the Current ($I$), we need to rearrange the formula:
$ \frac{P}{R} = I^2 $
$ I = \sqrt{\frac{P}{R}} $
Substitute the given values into the derived formula:
$ I = \sqrt{\frac{100 \, \text{W}}{4 \, \Omega}} $
$ I = \sqrt{25 \, \text{A}^2} $
$ I = 5 \, \text{A} $
The calculated Current ($I$) is 5 A.
Two electric bulbs marked 25 W - 220 V and 100 W - 220 V are connected in series with 440 V supply. Which of the bulb will fuse?
Two heaters are marked 200V,300W & 200V,600W. If the heaters are connected in series and the combination connected in series and the combination connected to a 200 V dc supply, then which option is true out of the following?