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Question

When the potential difference across a resistive conductor of resistance R obeying ohm's law, is doubled, the rate of generation of heat will become

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
Four times

Heat Generation Rate Formula

The rate of heat generation in a resistive conductor is equivalent to the electrical power (P) dissipated by it. According to Ohm's law, the relationship between power, potential difference (\(V\)), and resistance (\(R\)) is given by:

\(P = \frac{V^2}{R}\)

This formula shows that the rate of heat generation (\(P\)) is directly proportional to the square of the potential difference (\(V^2\)) and inversely proportional to the resistance (\(R\)).

Power Change Calculation

Let the initial potential difference be \(V_1\) and the initial rate of heat generation be \(P_1\). Using the formula:

\(P_1 = \frac{V_1^2}{R}\)

The question states that the potential difference is doubled. Let the new potential difference be \(V_2\). Therefore:

\(V_2 = 2V_1\)

Let the new rate of heat generation be \(P_2\). Substituting \(V_2\) into the power formula:

\(P_2 = \frac{V_2^2}{R} = \frac{(2V_1)^2}{R}\)

Simplifying the expression for \(P_2\):

\(P_2 = \frac{4V_1^2}{R}\)

Now, compare \(P_2\) with the initial power \(P_1\):

\(P_2 = 4 \times \left( \frac{V_1^2}{R} \right) = 4P_1\)

Thus, when the potential difference is doubled, the rate of generation of heat becomes four times the original rate.

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