To find the power of the electric bulb, we use the fundamental relationship between electrical power, voltage, and current.
The formula relating power (\(P\)), voltage (\(V\)), and current (\(I\)) is:
\(P = V \times I\)
\(P = 200 \text{ V} \times 0.5 \text{ A}\)
\(P = 100 \text{ W}\)
The power of the bulb is 100 Watts (W).
Therefore, the correct option is the one representing 100 W.
Two electric bulbs marked 25 W - 220 V and 100 W - 220 V are connected in series with 440 V supply. Which of the bulb will fuse?
Two heaters are marked 200V,300W & 200V,600W. If the heaters are connected in series and the combination connected in series and the combination connected to a 200 V dc supply, then which option is true out of the following?