The power dissipated by a resistor can be calculated using the formula \(P = \frac{V^2}{R}\), where \(P\) is the power in watts, \(V\) is the potential difference in volts, and \(R\) is the resistance in ohms. We are given that the resistor generates 200 J of heat every second, which means its power is 200 W (since 1 watt = 1 joule/second). The resistance is 8 Ω.
We can rearrange the formula to solve for \(V\):
\(V = \sqrt{PR}\)
Substituting the given values:
\(V = \sqrt{200 \, W \times 8 \, \Omega} = \sqrt{1600 \, W\Omega} = 40 \, V\)
Therefore, the potential difference across the resistor is 40 V.
Two electric bulbs marked 25 W - 220 V and 100 W - 220 V are connected in series with 440 V supply. Which of the bulb will fuse?
Two heaters are marked 200V,300W & 200V,600W. If the heaters are connected in series and the combination connected in series and the combination connected to a 200 V dc supply, then which option is true out of the following?