400 J
The heat energy generated by the bulb can be calculated using the formula for electrical power and energy:
Power (P) = Voltage (V) × Current (I)
Given:
Therefore, the power consumed by the bulb is:
P = 10 V × 2 A = 20 W
Energy (E) = Power (P) × Time (t)
Given:
Therefore, the heat energy generated by the bulb is:
E = 20 W × 20 s = 400 J
Thus, the correct answer is 400 J.
Two electric bulbs marked 25 W - 220 V and 100 W - 220 V are connected in series with 440 V supply. Which of the bulb will fuse?
Two heaters are marked 200V,300W & 200V,600W. If the heaters are connected in series and the combination connected in series and the combination connected to a 200 V dc supply, then which option is true out of the following?