1. Identify Question Type:

This is a numerical reasoning problem based on the principles of electricity in Physics. It requires the application of the formula for electric power.

2. Understand the Given Information:

• Voltage of the battery (V) = 6 V
• Total current in the circuit (I) = 0.6 A
• Connection of bulbs: Three identical bulbs in parallel.

The question asks for the total power dissipated by the battery, which is the total power supplied to the entire circuit.

3. Step-by-Step Solution:

Step 1: Identify the relevant formula. The electric power (P) dissipated in a circuit is calculated by the product of the total voltage (V) across the circuit and the total current (I) flowing through it.

The formula is: P = V × I

Step 2: Substitute the given values into the formula.

• V = 6 V
• I = 0.6 A

P = 6 V × 0.6 A

Step 3: Calculate the power.

P = 3.6 W

The unit of power is Watts (W).

Note: The information that there are "three identical bulbs" connected "in parallel" is extra information. While consistent with the given voltage and current, it is not needed to calculate the total power dissipated by the battery, as we are already given the total voltage and total current.

4. State the Core Logic/Pattern:

The core logic is the direct application of the electric power formula, P = V × I, using the total voltage supplied by the battery and the total current drawn from it to find the total power dissipated.

5. Eliminate Incorrect Options:

• Option 1 (0.1 W): This is incorrect. It might be obtained by incorrectly dividing the current by the voltage (0.6 / 6 = 0.1).
• Option 3 (5 W): This is an incorrect calculation and does not correspond to any standard formula with the given values.
• Option 4 (10 W): This is incorrect. This value is obtained by dividing voltage by current (6 / 0.6 = 10), which calculates the equivalent resistance (in Ohms, Ω) of the circuit, not the power (in Watts, W).

Therefore, the correct power dissipated by the battery is 3.6 W.