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Question

If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

1

Solution:  Using Substitution

Step 1: Choose a convenient angle for A

The core idea of this method is to choose a value for angle A that simplifies the trigonometric functions (sin A and cos A). A perfect choice is A = 90°, because sin(90°) = 1 and cos(90°) = 0, which are easy numbers to work with.

Step 2: Solve for 'p' using the chosen angle

Substitute A = 90° into the given equation:

p sin(90°) − cos(90°) = 1

Since sin(90°) = 1 and cos(90°) = 0, the equation becomes:

p(1) − 0 = 1

This simplifies directly to:

p = 1

Step 3: Evaluate the target expression

Now we substitute the values we have (A = 90°, cos(90°) = 0, and p = 1) into the expression we need to find:

p² − (1 + p²) cos A

Plugging in the values:

(1)² − (1 + (1)²) cos(90°)

Simplify the terms inside the parentheses:

1 − (1 + 1) × 0 
1 − (2) × 0

Any number multiplied by zero is zero:

1 − 0

Result = 1

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Similar Questions

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Important Questions from Trigonometry

  1. If A is an acute angle and tanA + cotA = 2, find the value of 7tan⁸A – 6cot⁸A + 8sec²A.

  2. If p = sinA / (1 + cosA), then sinA / (1 - cosA) is equal to:

  3. In a ΔABC, right-angled at B if tanC = √3, then find (sin²C + cos²C) / (1 + cot²C).

  4. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  5. For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:

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