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Question

If \[ \frac{\sec \alpha + \tan \alpha}{\sec \alpha - \tan \alpha} = \frac{7}{4}, \] then find the value of \( \csc \alpha \).

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

11/3

Given:
 

\[\frac{\sec \alpha + \tan \alpha}{\sec \alpha - \tan \alpha} = \frac{7}{4}\]

Let:
 

\[x = \sec \alpha, \quad y = \tan \alpha\]

Then the equation becomes:
 

\[\frac{x + y}{x - y} = \frac{7}{4}\]

Cross-multiplying:
 

\[4(x + y) = 7(x - y)\]

Expanding both sides:
 

\[4x + 4y = 7x - 7y\]

Bringing all terms to one side:
 

\[4x + 4y - 7x + 7y = 0 \Rightarrow -3x + 11y = 0 \Rightarrow 11y = 3x \Rightarrow \frac{y}{x} = \frac{3}{11}\]

Recall the identity:
 

\[\frac{\tan \alpha}{\sec \alpha} = \sin \alpha \Rightarrow \sin \alpha = \frac{3}{11}\]

Therefore:
 

\[\csc \alpha = \frac{1}{\sin \alpha} = \frac{11}{3}\]

Final Answer:
 

\[\boxed{\csc \alpha = \frac{11}{3}}\]
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Similar Questions

  1. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  2. For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:

  3. If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

  4. Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]

  5. Using
    \[ \cot(A − B) = \frac{\cot A \cot B + 1}{\cot B − \cot A} \]
    Find the value of cot 15°

  6. The greatest value of sin⁴θ + cos⁴θ is:

  7. If (48° + k) is an acute angle and sin(48° + k) = cos13°, what is the value of k (in °)?

  8. If A is an acute angle and tanA + cotA = 2, find the value of 7tan⁸A – 6cot⁸A + 8sec²A.

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Important Questions from Trigonometry

  1. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  2. For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:

  3. If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

  4. Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]

  5. Using
    \[ \cot(A − B) = \frac{\cot A \cot B + 1}{\cot B − \cot A} \]
    Find the value of cot 15°

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