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Question

If p = sinA / (1 + cosA), then sinA / (1 - cosA) is equal to:

This question was previously asked in
SSC CGL 2024 (Tier-I) Previous Year Paper (17-Sep-2024) (Shift 3)
The correct answer is

1 / p

By simplifying the expression for p, we find that sinA / (1 - cosA) is equal to 1 / p.

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Similar Questions

  1. If A is an acute angle and tanA + cotA = 2, find the value of 7tan⁸A – 6cot⁸A + 8sec²A.

  2. In a ΔABC, right-angled at B if tanC = √3, then find (sin²C + cos²C) / (1 + cot²C).

  3. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  4. For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:

  5. If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

  6. Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]

  7. If (48° + k) is an acute angle and sin(48° + k) = cos13°, what is the value of k (in °)?

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  9. Using
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    Find the value of cot 15°

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Important Questions from Trigonometry

  1. If A is an acute angle and tanA + cotA = 2, find the value of 7tan⁸A – 6cot⁸A + 8sec²A.

  2. In a ΔABC, right-angled at B if tanC = √3, then find (sin²C + cos²C) / (1 + cot²C).

  3. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  4. For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:

  5. If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

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