If 8cotθ = 7, then the value of (1 + sinθ) / cosθ) is:
(8 + √113) / 7
Given
8cotθ = 7, we express cotθ as 7/8 and use trigonometric identities.
Solving for sinθ and cosθ using Pythagorean theorem, we substitute in the given expression.
The correct simplified value is (8 + √113) / 7.
Similar Questions
If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?
For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:
If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:
Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]
Using
\[ \cot(A − B) = \frac{\cot A \cot B + 1}{\cot B − \cot A} \]
Find the value of cot 15°If \[ \frac{\sec \alpha + \tan \alpha}{\sec \alpha - \tan \alpha} = \frac{7}{4}, \] then find the value of \( \csc \alpha \).
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Important Questions from Trigonometry
If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?
For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:
If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:
Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]
Using
\[ \cot(A − B) = \frac{\cot A \cot B + 1}{\cot B − \cot A} \]
Find the value of cot 15°
