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Question

For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

1

cos²θ + cos⁴θ = cos²θ(1 + cos²θ).
. Hence, the answer is 1

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Similar Questions

  1. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  2. If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

  3. Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]

  4. Using
    \[ \cot(A − B) = \frac{\cot A \cot B + 1}{\cot B − \cot A} \]
    Find the value of cot 15°

  5. If \[ \frac{\sec \alpha + \tan \alpha}{\sec \alpha - \tan \alpha} = \frac{7}{4}, \] then find the value of \( \csc \alpha \).

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Important Questions from Trigonometry

  1. If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?

  2. If p sin A − cos A = 1, then p2 − (1 + p2) cos A equals:

  3. Evaluate the given expression. \[\frac{5}{1+\cot^2\theta} + \frac{3}{1+\tan^2\theta} + 2\cos^2\theta\]

  4. Using
    \[ \cot(A − B) = \frac{\cot A \cot B + 1}{\cot B − \cot A} \]
    Find the value of cot 15°

  5. If \[ \frac{\sec \alpha + \tan \alpha}{\sec \alpha - \tan \alpha} = \frac{7}{4}, \] then find the value of \( \csc \alpha \).

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