In a ΔABC, right-angled at B if tanC = √3, then find (sin²C + cos²C) / (1 + cot²C).
3 / 4
By using the identity sin²C + cos²C = 1 and substituting the value of tanC = √3, we get the result as 3/4.
Similar Questions
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Important Questions from Trigonometry
If A is an acute angle and tanA + cotA = 2, find the value of 7tan⁸A – 6cot⁸A + 8sec²A.
If p = sinA / (1 + cosA), then sinA / (1 - cosA) is equal to:
If 8cotθ = 7, then the value of (1 + sinθ) / cosθ) is:
For any acute angle θ, sin²θ + cos²θ = 1. Then the value of cos²θ + cos⁴θ is:
If 2 Cot x = 5, then what is (2 Cos x - Sin x) / (2 Cos x + Sin x) equal to?
