If a + b = 10 and ab = 16, find the value of a² + b².
68
Using the identity \((a+b)^2 = a^2+b^2+2ab\), we get \(a^2+b^2 = (a+b)^2-2ab\).
Substituting the given values: \(a^2+b^2 = 10^2 - 2(16) = 100-32\).
Therefore, \(a^2+b^2 = 68\).
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Important Questions from Identities
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:
- \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?
If a + b + c = 5, a 2+ b 2+ c 2= 27, a 3 + b 3 + c 3 = 125, then the value of \(\frac{abc}{5}\) is:
(999) 2- 2 2=
