If p + q = 6 and pq = 5, find p³ + q³.
126
Using the identity \(p^3+q^3 = (p+q)^3 - 3pq(p+q)\).
Substituting the given values: \(p^3+q^3 = 6^3 - 3(5)(6) = 216-90\).
Therefore, \(p^3+q^3 = 126\).
Similar Questions
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Important Questions from Identities
Simplify.
\(\frac{2.5 \times 2.5 \times 2.5-1.5 \times 1.5 \times 1.5}{2.5 \times 2.5+2.5 \times 1.5+1.5 \times 1.5}\)
If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of \(27x^3+{{1} \over 8x^3}\) ?
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:
- \(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)
- \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
