If p + q = 6 and pq = 5, find p³ + q³.
126
Using the identity \(p^3+q^3 = (p+q)^3 - 3pq(p+q)\).
Substituting the given values: \(p^3+q^3 = 6^3 - 3(5)(6) = 216-90\).
Therefore, \(p^3+q^3 = 126\).
If a + b = 10 and ab = 16, find the value of a² + b².
If x + y = 6 and x² + y² = 20, find x⁴ + y⁴.
If x + y + z = 3 and xy + yz + zx = 3, find x³ + y³ + z³.
If a + b = 5 and a² + b² = 17, find (a³ + b³)/ab.
If p + q = 4 and p2 + q2 = 10, find p4 + q4 - 2p2q2.
If y + 1/y = 5, find the value of y2 + 1/y2 + 5.
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:
If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?
If a + b + c = 5, a 2+ b 2+ c 2= 27, a 3 + b 3 + c 3 = 125, then the value of \(\frac{abc}{5}\) is:
(999) 2- 2 2=