For the circuit shown in the figure, the current through the resistor $R_2$ is ___________.
2.8 mA
This problem requires Mesh Analysis applied to the circuit shown in the figure.
Mesh Analysis procedure:
The correct answer (Option 2) corresponds to the circuit shown in the original question paper.
In the given circuit R = 6Ω, R = 4Ω and R = 3Ω. The voltage sources are $V_1 = 21V$ and $V_2= 5V$. Determine the currents flowing through $R_1$ and $R_2$ respectively.

Which of the following laws is applied for mesh analysis of the network?
For the circuit given below, which are the correct two equations of Mesh current ?

(A) 12I1 – 5I2 – 4I3 = –24
(B) 5I1 + 18I2 + 6I3 = –112
(C) –4I1 – 6I2 + 18I3 = –106
(D) 2I1 + 3I2 – 7I3 = 106
(E) –5I1 + 24I2 – 6I3 = 116
Choose the most appropriate answer from the options given below :
Consider a two-mesh network as shown in the figure :

The values of I1 and Ibd and I2 are computed as
(a) I1 = 1.885 amps, I2 = 0.341 amps
(b) I1 = 1.885 amps, Ibd = 2.23 amps
(c) I2 = –0.341 amps, Ibd = 1.885 amps
(d) I2 = –0.341 amps, Ibd = 2.23 amps
Which of the above computations are correct ?
Assertion (A) : It is convenient to write loop equations for a network containing voltage source but no current source.
Reason (R) : If the current sources are present, then these must be first converted into their equivalent voltage sources.
Select your answer using the codes given below.

In the above mentioned figure, how much is the voltage around partial loop cefd and how much is the voltage around loop cefdc ?