Consider the following code snippet in C programming language. int n = 5; int m = n++; What is the value of m after execution?
5
To determine the value of m after the execution of the given C code snippet, let's analyze the code step-by-step:
-
The code begins by initializing an integer variable
nwith the value 5:int n = 5; -
Next, another integer variable
mis declared and assigned the value ofn++:int m = n++;-
Here,
n++is the postfix increment operator. In postfix incrementation, the current value ofnis used in the expression, and thennis incremented by 1. - The current value of
nbefore the increment is 5. - This value 5 is assigned to
m. - After the assignment,
nis incremented, makingn = 6.
-
Here,
Thus, after executing the code, the value of m is 5. This is because the postfix operator uses the value before incrementation.
Conclusion: The value of m after execution is 5. Therefore, the correct answer is 5.
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void f(int x)
{
x = x + 5;
}
int main()
{
int a = 10;
f(a);
printf("%d",a);
return 0;
}
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