Read the following passage and answer the questions that follow : Diffusion of impurity atoms in silicon is important in silicon integrated circuit processing. The idea of using diffusion techniques to alter the type of conductivity in silicon or germanium was disclosed in a patent by Pfann. Since then various ways of introducing dopants into silicon by diffusion have been studied with the goal of controlling dopant distribution, total dopant concentration, its uniformity reproducibility, and of processing a large number of device wafers in a batch to reduce the manufacturing cost. The diffusion is used to form bases, emitters and resistors in bipolar devices technology, to form source and drain regions and to dope polysilicon in MOS device technology. Dopant atoms that span a wide range of concentrations can be introduced into silicon in many ways.
Fick's second law of diffusion in one dimensional form can be expressed as :
\(\dfrac{\partial C(x,t)}{\partial t}=\dfrac{\partial}{\partial x}\left[D\dfrac{\partial C(x,t)}{\partial x}\right]\)
Fick's second law is a time derivative on the left and a space derivative twice on the right — option 1:
\(\dfrac{\partial C}{\partial t}=\dfrac{\partial}{\partial x}\left[D\dfrac{\partial C}{\partial x}\right]\)
Where it comes from — two statements combined.
Fick's first law says that flux is driven by a concentration gradient, and flows down it:
\(J=-D\dfrac{\partial C}{\partial x}\)
Continuity says that whatever does not flow out must accumulate:
\(\dfrac{\partial C}{\partial t}=-\dfrac{\partial J}{\partial x}\)
Substituting the first into the second gives the second law directly, and the two minus signs cancel. Seeing this derivation makes the structure inevitable: the left side is a rate of accumulation in time, and the right is the divergence of a flux in space. The two sides must therefore carry different variables, which immediately rules out options 2, 3 and 4 — each of which differentiates twice with respect to the same variable somewhere.
Checking option 1 dimensionally. With C in cm–3 and D in cm2/s:
\(\left[\dfrac{\partial C}{\partial t}\right]=\dfrac{\text{cm}^{-3}}{\text{s}},\qquad \left[\dfrac{\partial^{2}C}{\partial x^{2}}\right]=\dfrac{\text{cm}^{-3}}{\text{cm}^{2}}\)
and multiplying the second by D's cm2/s reproduces the first exactly. None of the other three balances.
Why D is left inside the derivative. If diffusivity is constant the equation simplifies to \(\partial C/\partial t=D\,\partial^{2}C/\partial x^{2}\), whose solutions are the Gaussian and error-function profiles of the previous questions. But D is not always constant: at concentrations above the intrinsic carrier density it becomes concentration dependent through the charged point defects that carry the dopant, so \(D=D(C)\) and the general form must be kept. That is why heavily doped profiles are box-shaped rather than Gaussian.
The same equation governs heat conduction, with temperature in place of concentration — which is why solutions worked out for one field transfer directly to the other.
Hence, the correct expression is option 1.
When silicon dioxide of thickness d is grown, the Silicon consumed is :
Match List - I with List - II.
| List - I | List - II |
| (A) Annealing | (I) Isolation |
| (B) Sealing | (II) Doping |
| (C) Ion implantation | (III) Packing density |
| (D) Oxidation | (IV) Crystal restoration |
Choose the correct answer from the options given below :
Arrange the following in ascending order based on their diffusivity :
(A) Boron
(B) Arsenic
(C) Antimony
(D) Phosphorus
Choose the most appropriate answer from the options given below :
A thin layer of dopant is deposited onto silicon surface with a fixed total amount of dopants QT per unit area. If D is the diffusivity of dopants, then the surface concentration is :
The idea of using diffusion techniques was disclosed in patent by Pfann in the year :
The diffusivity determined experimentally over a range of diffusion temperatures can be expressed as :
For a diffused layer that forms a p-n junction an average sheet resistance RS is defined and related to junction depth xj, the carrier mobility μ, and impurity distribution C(x) as :
Match the following :
| List - I | List - II |
| (a) Lift - off | (i) Fick's Equation |
| (b) Dry Etching | (ii) PMMA (Poly Methyl Methacrylate) |
| (c) Lithography | (iii) Bombardment of Plasma |
| (d) Diffusion | (iv) Structures of Target Material on the Surface of Substrate |
Codes :
Match the following :
| List - I | List - II |
| (a) Lift OFF | (i) Etching |
| (b) Rant's Rule | (ii) Crystal Growtd |
| (c) Hydrofluoric acid | (iii) Packaging |
| (d) Float zone | (iv) Metallisation |
Codes :
What is the name of adhesion promoter used in case of positive photo resist ?
A. For impurity diffusion in semiconductor, concentration gradient is the only essential requirement.
B. Annealing is a mandatory step after ion-implantation.
C. Wet etching is normally anisotropic
D. High temperature is required for the growth of $SiO_2$ because oxidation reaction takes place at high temperature
E. Bird's beak formation is a characteristic of LOCOS isolation
Choose the correct answer from the options given below:
Arrange the given process steps in sequence for self-aligned gate formation.
A. Thermal oxidation to grow gate oxide.
B. Polysilicon deposition
C. Photolithography using gate mask
D. Etching of polysilicon and oxide
E. Source/drain diffusion
Choose the correct answer from the options given below:
| LIST-I | LIST-II |
| A. Shallow trench isolation (STI) | I. Low static power dissipation |
| B. Junction isolation | II. High static power dissipation |
| C. CMOS technology | III. High component density |
| D. Bipolar IC technology | IV. Low component density |
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R
Assertion A: Impurity diffusion in semiconductor essentially needs very high temperature.
Reason R: Diffusivity of impurity atoms is negligibly small at room temperature.
In the light of the above statements, choose the most appropriate answer from the options given below