Consider the following schematic plots of orbital wavefunction ($\Psi_r$) against distance ($r$) from the nucleus.
The figure representing two radial nodes in the orbital is
To determine which schematic plot represents two radial nodes in the orbital, we need to understand the concept of radial nodes in quantum chemistry. Radial nodes are the points where the radial wavefunction $\Psi_r$ becomes zero, excluding the nucleus.
For a given orbital, the total number of nodes is given by:
\(n - \ell - 1\)
where \(n\) is the principal quantum number and \(\ell\) is the azimuthal quantum number (orbital angular momentum quantum number). Radial nodes are given by \(n - \ell - 1\).
Let's analyze the schematics in the provided image:
Based on the analysis, Plot C has two points where $\Psi_r$ is zero (excluding the nucleus), which shows that it has two radial nodes. Therefore, the correct answer is Option C.
For a certain reaction R $\rightarrow$ Product, the plot of [R] vs time has a negative slope as shown. The order of reaction is :

| List I (Order of reaction) | List II (Unit of rate constant) |
| A. Zero order | I. $mol^{-1} L s^{-1}$ |
| B. First order | II. $mol^{-2} L^2 s^{-1}$ |
| C. Second order | III. $s^{-1}$ |
| D. Third order | IV. $mol L^{-1} s^{-1}$ |
Calculate emf of the half cell given below :
$$Pt(s) | H_2 (g, 2 \text{ atm}) | HCl (aq, 0.02 \text{ M})$$
$$E_{H_2 /H^+}^\circ = 0 \text{ V}$$
(Given : $\frac{2.303 RT}{F} = 0.059$, $\log 2 = 0.3010$)
At 298 K, a certain buffer solution contains equal concentrations of $X^{-}$ and $HX$. $K_b$ for $X^-$ is $10^{-10}$. What is the pH of this buffer solution ?