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At a certain temperature T (K), during a process, 500 J is absorbed by the system and work of 200 J is done by the system. Then change in internal energy of the system is :

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
300 J

Understanding First Law of Thermodynamics

This question relates to the First Law of Thermodynamics, which describes the conservation of energy. The law states that the change in internal energy ($\Delta U$) of a system is equal to the heat added to the system ($Q$) minus the work done by the system ($W$).

Applying the Formula

The formula for the First Law of Thermodynamics is:

$ \Delta U = Q - W $

  • Heat Absorbed ($Q$): The system absorbs 500 J, so $Q = +500$ J.
  • Work Done ($W$): The work is done *by* the system, which is 200 J. In the formula $\Delta U = Q - W$, work done *by* the system is taken as positive. So, $W = +200$ J.

Calculating Internal Energy Change

Substitute the given values into the First Law equation:

$ \Delta U = 500 \text{ J} - 200 \text{ J} $

$ \Delta U = 300 \text{ J} $

Therefore, the change in internal energy of the system is 300 J.

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