This question relates to the First Law of Thermodynamics, which describes the conservation of energy. The law states that the change in internal energy ($\Delta U$) of a system is equal to the heat added to the system ($Q$) minus the work done by the system ($W$).
The formula for the First Law of Thermodynamics is:
$ \Delta U = Q - W $
Substitute the given values into the First Law equation:
$ \Delta U = 500 \text{ J} - 200 \text{ J} $
$ \Delta U = 300 \text{ J} $
Therefore, the change in internal energy of the system is 300 J.
| List I (Order of reaction) | List II (Unit of rate constant) |
| A. Zero order | I. $mol^{-1} L s^{-1}$ |
| B. First order | II. $mol^{-2} L^2 s^{-1}$ |
| C. Second order | III. $s^{-1}$ |
| D. Third order | IV. $mol L^{-1} s^{-1}$ |
Consider the following reaction :
$2A (g) + B (g) \rightarrow 2D (g)$
$\Delta U^\ominus = -10 \text{ kJ mol}^{-1}$ and $\Delta S^\ominus = -44 \text{ J K}^{-1}$ at 298 K.
Identify the correct option with $\Delta G^\ominus$ for the reaction and spontaneity of the reaction at 298 K. (Given : $R = 8.31 \text{ J mol}^{-1} \text{K}^{-1}$)
For a certain reaction R $\rightarrow$ Product, the plot of [R] vs time has a negative slope as shown. The order of reaction is :

At 298 K, a certain buffer solution contains equal concentrations of $X^{-}$ and $HX$. $K_b$ for $X^-$ is $10^{-10}$. What is the pH of this buffer solution ?