An object is accelerating at 5 m/s2 from its rest position. The velocity of this object after 5 s is:
25 m/s
The question asks us to find the velocity of an object after a specific time, given its initial state (at rest) and its constant acceleration.
We are provided with the following information:
We need to find the final velocity (\(v\)) of the object after 5 seconds.
To solve this problem, we can use the first equation of motion (kinematic equation), which relates initial velocity, final velocity, acceleration, and time for objects moving with constant acceleration:
\(v = u + at\)
Where:
Now, we substitute the given values into the equation:
\(v = 0 \text{ m/s} + (5 \text{ m/s}^2)(5 \text{ s})\)
Performing the multiplication:
\(v = 0 \text{ m/s} + 25 \text{ m/s}\)
Calculating the final velocity:
\(v = 25 \text{ m/s}\)
Thus, the velocity of the object after 5 seconds is 25 m/s.
Let's compare this result with the given options:
| Option | Velocity | Matches our result? |
|---|---|---|
| 1 | 15 m/s | No |
| 2 | 20 m/s | No |
| 3 | 5 m/s | No |
| 4 | 25 m/s | Yes |
The calculated velocity of 25 m/s matches Option 4.
Here are the primary kinematic equations used for motion with constant acceleration:
| Equation | Variables Involved | When to Use |
|---|---|---|
| \(v = u + at\) | v, u, a, t | To find final velocity (v) or time (t) when displacement is not involved. |
| \(s = ut + \frac{1}{2}at^2\) | s, u, a, t | To find displacement (s) or time (t) when final velocity is not involved. |
| \(v^2 = u^2 + 2as\) | v, u, a, s | To find final velocity (v) or displacement (s) when time is not involved. |
| \(s = \frac{(u+v)t}{2}\) | s, u, v, t | To find displacement (s) or time (t) when acceleration is not involved. |
In these equations:
Acceleration is defined as the rate of change of velocity of an object. It is a vector quantity, meaning it has both magnitude and direction. The unit of acceleration is meters per second squared (\(m/s^2\)) in the SI system.
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