Question
A pentagon is divided into three triangles by drawing diagonals from one of its vertices. The areas of two of these triangles are 24 cm2 and 30 cm2. The third triangle has a base of 12 cm and a height of 38 cm. What is the area (in cm2) of the pentagon?
This question was previously asked in
RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is
282
Area of the third triangle: \(\tfrac12\times12\times38 = 228\) cm2.
Total area of the pentagon: \(24+30+228 = 282\) cm2.
Hence, the area of the pentagon is 282 cm2.
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