The problem requires calculating the total area swept by two car wipers that do not overlap.
Each wiper sweeps out a sector of a circle. The area of a sector is calculated using the formula:
\(A_{sector} = \frac{\theta}{360^\circ} \times \pi r^2\)
Where:
Given values:
Substitute these values into the sector area formula:
\(A_{single} = \frac{126^\circ}{360^\circ} \times \frac{22}{7} \times (18 \text{ cm})^2\)
Simplify the angle fraction:
\(\frac{126}{360} = \frac{7}{20}\)
Calculate the square of the radius:
\((18 \text{ cm})^2 = 324 \text{ cm}^2\)
Calculate the area for one wiper:
\(A_{single} = \frac{7}{20} \times \frac{22}{7} \times 324 \text{ cm}^2\)
Cancel out the 7s:
\(A_{single} = \frac{1}{20} \times 22 \times 324 \text{ cm}^2\)
\(A_{single} = \frac{11}{10} \times 324 \text{ cm}^2\)
\(A_{single} = 1.1 \times 324 \text{ cm}^2 = 356.4 \text{ cm}^2\)
Since there are two wipers and they do not overlap, the total cleaned area is twice the area swept by a single wiper.
\(A_{total} = 2 \times A_{single}\)
\(A_{total} = 2 \times 356.4 \text{ cm}^2\)
\(A_{total} = 712.8 \text{ cm}^2\)
The total area cleaned by the blades is \(712.8 \text{ cm}^2\).
The inner and outer diameters of ring 1 of a dartboard are 15 cm and 17 cm respectively and those of ring II are 12 cm and 13 cm respectively. What is the total area of these two rings?

\(ABCD\) is a diameter of a circle of radius 12 cm. The lengths \(AB\), \(BC\) and \(CD\) are equal. Semi-circles are drawn on \(AB\) and \(BD\) as diameters as shown in the given figure. Find area of the shaded region.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?