To find the total cost of fencing the rectangular field, we first need to determine its perimeter. We are given the length and the area of the field.
The area (\(A\)) of a rectangle is calculated by multiplying its length (\(L\)) and width (\(W\)). We have:
Using the area formula \(A = L \times W\), we can find the width:
\(W = \frac{A}{L} = \frac{3000 \, \text{m}^2}{200 \, \text{m}} = 15 \, \text{m}\)
The perimeter (\(P\)) of a rectangle is calculated using the formula \(P = 2 \times (L + W)\). Now that we know the length and width:
Calculate the perimeter:
\(P = 2 \times (200 \, \text{m} + 15 \, \text{m}) = 2 \times (215 \, \text{m}) = 430 \, \text{m}\)
The cost of fencing is given as 5 rupees per metre. To find the total cost, multiply the perimeter by the cost per metre:
Total Cost = \(P \times \text{Cost per metre}\)
\(\text{Total Cost} = 430 \, \text{m} \times 5 \, \text{rupees/m} = 2150 \, \text{rupees}\)
Therefore, the total cost of fencing the field is 2150 rupees.
The inner and outer diameters of ring 1 of a dartboard are 15 cm and 17 cm respectively and those of ring II are 12 cm and 13 cm respectively. What is the total area of these two rings?

\(ABCD\) is a diameter of a circle of radius 12 cm. The lengths \(AB\), \(BC\) and \(CD\) are equal. Semi-circles are drawn on \(AB\) and \(BD\) as diameters as shown in the given figure. Find area of the shaded region.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?