The problem requires finding the total length of tape needed to cover all four sides of a rectangular board. This is equivalent to calculating the perimeter of the rectangle.
The tape needs to cover all four sides, so the required tape length is the perimeter of the rectangle. The formula for the perimeter \(P\) of a rectangle is:
\(P = 2 \times (L + B)\)
Substitute the given values into the formula:
\(P = 2 \times (12 \text{ cm} + 3 \text{ cm})\)
First, calculate the sum of the length and breadth:
\(P = 2 \times (15 \text{ cm})\)
Now, multiply by 2 to find the total perimeter:
\(P = 30 \text{ cm}\)
The tape should be 30 cm long to cover all four sides of the board.
The inner and outer diameters of ring 1 of a dartboard are 15 cm and 17 cm respectively and those of ring II are 12 cm and 13 cm respectively. What is the total area of these two rings?

\(ABCD\) is a diameter of a circle of radius 12 cm. The lengths \(AB\), \(BC\) and \(CD\) are equal. Semi-circles are drawn on \(AB\) and \(BD\) as diameters as shown in the given figure. Find area of the shaded region.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?