The area of the square is provided as \(196 \text{ cm}^2\). The area of a square is calculated using the formula \(A = s^2\), where \(s\) is the side length.
We set up the equation:
\(s^2 = 196 \text{ cm}^2\)
Taking the square root of both sides gives the side length:
\(s = \sqrt{196} \text{ cm} = 14 \text{ cm}\)
The problem states that the side length of the square (\(s\)) is equal to the diameter (\(d\)) of the circle.
So, the diameter of the circle is:
\(d = s = 14 \text{ cm}\)
The radius (\(r\)) of the circle is half of its diameter:
\(r = \frac{d}{2} = \frac{14 \text{ cm}}{2} = 7 \text{ cm}\)
The area of a circle is given by the formula \(A = \pi r^2\). We are instructed to use \(\pi = \frac{22}{7}\).
Substitute the radius and the value of \(\pi\) into the formula:
Area \(= \frac{22}{7} \times (7 \text{ cm})^2\)
Area \(= \frac{22}{7} \times 49 \text{ cm}^2\)
Simplify the calculation:
Area \(= 22 \times 7 \text{ cm}^2 = 154 \text{ cm}^2\)
The area of the circle is \(154 \text{ cm}^2\). This corresponds to Option A.
The inner and outer diameters of ring 1 of a dartboard are 15 cm and 17 cm respectively and those of ring II are 12 cm and 13 cm respectively. What is the total area of these two rings?

\(ABCD\) is a diameter of a circle of radius 12 cm. The lengths \(AB\), \(BC\) and \(CD\) are equal. Semi-circles are drawn on \(AB\) and \(BD\) as diameters as shown in the given figure. Find area of the shaded region.
The shorter side of a rectangle is 15 cm less than the longer side. The numerical value of its area is equal to 5 times the numerical value of its perimeter. What is the length (in cm) of its longer side?