4 years ago, the age of Shyam was seven times the age of his son, Rajat. After 8 years, Shyam’s age will be three times the age of Rajat. Find the present age of Shyam.
46 years
Let Shyam's present age be \(S\) years and Rajat's present age be \(R\) years.
4 years ago: \(S - 4 = 7(R - 4)\), which gives \(S = 7R - 24\).
After 8 years: \(S + 8 = 3(R + 8)\), which gives \(S = 3R + 16\).
Equating both: \(7R - 24 = 3R + 16\), so \(4R = 40\), hence \(R = 10\).
Then \(S = 7(10) - 24 = 46\).
Hence, Shyam's present age is 46 years.
The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. The present age of Dr. Pandey's son is?
Three years ago, the average age of a family of six members was 19 years. Since then, a boy has been born, and the average age of the family is the same today as it was three years ago. What is the age of the boy?
Amita is 2 years older than her friend Amrita. Amita's father is twice as old as Amita, and Amrita is twice as old as her sister. The ages of Amita's father and Amrita's sister differ by 43 years. The sum of the ages (in years) of Amita and Amrita is: