To find the simple interest (SI), we use the formula:
\( SI = \frac{P \times T \times R}{100} \)
Where:
Substitute the given values into the formula:
\( SI = \frac{1450 \times 5 \times 5}{100} \)
First, multiply the principal, time, and rate:
\( 1450 \times 5 \times 5 = 1450 \times 25 \)
Calculate the product:
\( 1450 \times 25 = 36250 \)
Now, divide the result by 100:
\( SI = \frac{36250}{100} \)
\( SI = 362.5 \)
Therefore, the simple interest is ₹362.5.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
A sum of money lent on simple interest becomes \(7\over5\) of itself in 4 years. Find the rate of interest per annum.
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.