The question asks us to find the simple interest rate given the principal amount, the total amount after a certain period, and the time duration.
First, calculate the Simple Interest (SI) earned over the 4 years.
The formula for Simple Interest is:
\(SI = A - P\)
Substituting the given values:
\(SI = ₹1,550 - ₹1,250 = ₹300\)
Now, use the simple interest formula to find the rate (R).
The formula is:
\(SI = \frac{P \times R \times T}{100}\)
Rearrange the formula to solve for R:
\(R = \frac{SI \times 100}{P \times T}\)
Substitute the calculated and given values:
\(R = \frac{300 \times 100}{1250 \times 4}\)
\(R = \frac{30000}{5000}\)
\(R = 6\)
Therefore, the simple interest rate is 6%.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
A sum of money lent on simple interest becomes \(7\over5\) of itself in 4 years. Find the rate of interest per annum.
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.