This problem involves calculating the simple interest (SI) earned on an investment.
The formula for simple interest is:
$ $ SI = \frac{P \times R \times T}{100} $ $
Where:
Given values:
Substitute these values into the formula:
$ $ SI = \frac{2000 \times 8.5 \times 6}{100} $ $
The simple interest yielded is ₹ 1,020.
The calculated interest of ₹ 1,020 matches Option B.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
A sum of money lent on simple interest becomes \(7\over5\) of itself in 4 years. Find the rate of interest per annum.
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.