This problem asks us to find the duration required for an investment to grow from a starting amount to a final amount at a fixed annual simple interest rate.
We are given the following information:
The Simple Interest (SI) is the difference between the final amount and the principal amount.
The formula is: \(SI = A - P\)
Substituting the given values:
\(SI = ₹2,040 - ₹1,500\)
\(SI = ₹540\)
So, the total simple interest earned over the period is ₹540.
The formula for Simple Interest is:
\(SI = \frac{P \times R \times T}{100}\)
We need to find the time (T). We can rearrange the formula to solve for T:
\(T = \frac{SI \times 100}{P \times R}\)
Now, we plug the values of SI, P, and R into the rearranged formula:
\(T = \frac{540 \times 100}{1500 \times 8}\)
First, calculate the numerator: \(540 \times 100 = 54000\)
Next, calculate the denominator: \(1500 \times 8 = 12000\)
Now, divide the numerator by the denominator:
\(T = \frac{54000}{12000}\)
Simplify the fraction:
\(T = \frac{54}{12}\)
Divide 54 by 12:
\(T = 4.5\) years
This can also be expressed as a mixed fraction: \(4 \frac{1}{2}\) years.
It will take \(4 \frac{1}{2}\) years for ₹1,500 to become ₹2,040 at a simple interest rate of 8% per annum.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
A sum of money lent on simple interest becomes \(7\over5\) of itself in 4 years. Find the rate of interest per annum.
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.