The problem asks for the simple interest rate (R) given the principal amount (P), the total amount (A) after a certain time (T).
Simple Interest is the difference between the final amount and the principal amount.
\(\text{SI} = A - P\)
\(\text{SI} = ₹1,550 - ₹1,250 = ₹300\)
Use the formula for Simple Interest:
\(\text{SI} = \frac{P \times R \times T}{100}\)
Rearrange the formula to solve for R:
\(R = \frac{\text{SI} \times 100}{P \times T}\)
Substitute the known values:
\(R = \frac{300 \times 100}{1250 \times 4}\)
\(R = \frac{30000}{5000}\)
\(R = 6\)
The simple interest rate is 6%.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
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The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?
P borrowed an amount from Q at a simple interest of 10% p.a. At the end of the year, P paid back Rs 99000 which was 90% of what she owed. How much money did P borrow?
An amount becomes Rs. 3795 in 3 years and Rs. 4537.50 in \(7 \frac{1}{2}\) years on simple interest. Find the rate of interest per annum.