To find the principal sum (the initial amount of money) that earns a specific interest, we use the simple interest formula.
The formula for simple interest is:
\( I = \frac{P \times R \times T}{100} \)
Where:
We need to rearrange the formula to solve for \(P\):
\( P = \frac{I \times 100}{R \times T} \)
Now, substitute the given values into the rearranged formula:
\( P = \frac{480 \times 100}{8 \times 2} \)
Perform the calculation:
The principal sum that will earn an interest of ₹480 in 2 years at 8% simple interest per year is ₹3000.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest ?
Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.
The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?
P borrowed an amount from Q at a simple interest of 10% p.a. At the end of the year, P paid back Rs 99000 which was 90% of what she owed. How much money did P borrow?
An amount becomes Rs. 3795 in 3 years and Rs. 4537.50 in \(7 \frac{1}{2}\) years on simple interest. Find the rate of interest per annum.