Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.
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The question asks us to find the annual interest rate, denoted by x%, at which Nirav and Mehul borrowed money. We are given their principal amounts, the time period, and the difference in the simple interest paid by them.
Let's break down the information provided:
We need to use the formula for calculating simple interest to find the value of x.
The formula for calculating Simple Interest (SI) is:
$$SI = \frac{P \times R \times T}{100}$$
Where:
Let's calculate the simple interest for both Nirav and Mehul using the given information and the rate x%.
For Nirav:
Simple Interest for Nirav (SI₁):
$$SI_1 = \frac{4000 \times x \times 2.5}{100}$$
$$SI_1 = \frac{4000 \times x \times \frac{5}{2}}{100}$$
$$SI_1 = \frac{4000 \times x \times 5}{200}$$
$$SI_1 = \frac{20000x}{200}$$
$$SI_1 = 100x$$
For Mehul:
Simple Interest for Mehul (SI₂):
$$SI_2 = \frac{5000 \times x \times 2.5}{100}$$
$$SI_2 = \frac{5000 \times x \times \frac{5}{2}}{100}$$
$$SI_2 = \frac{5000 \times x \times 5}{200}$$
$$SI_2 = \frac{25000x}{200}$$
$$SI_2 = 125x$$
We know that Mehul paid Rs. 125 more interest than Nirav. So, the difference between their simple interests is 125.
$$SI_2 - SI_1 = 125$$
Substitute the expressions we found for SI₁ and SI₂:
$$125x - 100x = 125$$
Combine the terms with x:
$$25x = 125$$
Now, solve for x by dividing both sides by 25:
$$x = \frac{125}{25}$$
$$x = 5$$
The value of x is 5. This means the interest rate is 5% per annum.
Let's check if an interest rate of 5% results in the given interest difference.
Nirav's Interest:
$$SI_1 = \frac{4000 \times 5 \times 2.5}{100} = \frac{4000 \times 5 \times \frac{5}{2}}{100} = \frac{4000 \times 25}{200} = \frac{100000}{200} = 500$$
Nirav's interest is Rs. 500.
Mehul's Interest:
$$SI_2 = \frac{5000 \times 5 \times 2.5}{100} = \frac{5000 \times 5 \times \frac{5}{2}}{100} = \frac{5000 \times 25}{200} = \frac{125000}{200} = 625$$
Mehul's interest is Rs. 625.
Interest Difference:
$$SI_2 - SI_1 = 625 - 500 = 125$$
The difference in interest is Rs. 125, which matches the information given in the question. Thus, the calculated value of x = 5 is correct.
| Term | Definition | In this Problem |
|---|---|---|
| Principal (P) | The initial amount of money borrowed or lent. | Rs. 4000 (Nirav), Rs. 5000 (Mehul) |
| Rate (R) | The annual interest rate (usually in percent). | x% (what we need to find) |
| Time (T) | The duration for which the money is borrowed or lent (in years). | 2.5 years |
| Simple Interest (SI) | Interest calculated only on the principal amount. | SI₁ (Nirav), SI₂ (Mehul) SI₂ - SI₁ = 125 |
| Formula | $$SI = \frac{P \times R \times T}{100}$$ | Used to find SI₁ and SI₂ |
It's important to distinguish between simple interest and compound interest.
The formula for compound interest is different, and problems involving compound interest require a different approach.
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