All Exams Test series for 1 year @ ₹349 only
Question

Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.

The correct answer is

5

Understanding the Simple Interest Problem

The question asks us to find the annual interest rate, denoted by x%, at which Nirav and Mehul borrowed money. We are given their principal amounts, the time period, and the difference in the simple interest paid by them.

Let's break down the information provided:

  • Nirav's Principal (P₁): Rs. 4000
  • Mehul's Principal (P₂): Rs. 5000
  • Time Period (T): 2.5 years
  • Interest Rate (R): x% per annum
  • Mehul paid Rs. 125 more interest than Nirav. This means Simple Interest for Mehul (SI₂) - Simple Interest for Nirav (SI₁) = Rs. 125.

We need to use the formula for calculating simple interest to find the value of x.

Applying the Simple Interest Formula

The formula for calculating Simple Interest (SI) is:

$$SI = \frac{P \times R \times T}{100}$$

Where:

  • P is the Principal amount
  • R is the Rate of Interest per annum
  • T is the Time Period in years

Calculating Simple Interest for Nirav and Mehul

Let's calculate the simple interest for both Nirav and Mehul using the given information and the rate x%.

For Nirav:

  • Principal (P₁): 4000
  • Rate (R): x
  • Time (T): 2.5

Simple Interest for Nirav (SI₁):

$$SI_1 = \frac{4000 \times x \times 2.5}{100}$$

$$SI_1 = \frac{4000 \times x \times \frac{5}{2}}{100}$$

$$SI_1 = \frac{4000 \times x \times 5}{200}$$

$$SI_1 = \frac{20000x}{200}$$

$$SI_1 = 100x$$

For Mehul:

  • Principal (P₂): 5000
  • Rate (R): x
  • Time (T): 2.5

Simple Interest for Mehul (SI₂):

$$SI_2 = \frac{5000 \times x \times 2.5}{100}$$

$$SI_2 = \frac{5000 \times x \times \frac{5}{2}}{100}$$

$$SI_2 = \frac{5000 \times x \times 5}{200}$$

$$SI_2 = \frac{25000x}{200}$$

$$SI_2 = 125x$$

Using the Interest Difference to Find x

We know that Mehul paid Rs. 125 more interest than Nirav. So, the difference between their simple interests is 125.

$$SI_2 - SI_1 = 125$$

Substitute the expressions we found for SI₁ and SI₂:

$$125x - 100x = 125$$

Combine the terms with x:

$$25x = 125$$

Now, solve for x by dividing both sides by 25:

$$x = \frac{125}{25}$$

$$x = 5$$

The value of x is 5. This means the interest rate is 5% per annum.

Verification of the Calculated Rate

Let's check if an interest rate of 5% results in the given interest difference.

  • Rate (R) = 5%
  • Time (T) = 2.5 years

Nirav's Interest:

$$SI_1 = \frac{4000 \times 5 \times 2.5}{100} = \frac{4000 \times 5 \times \frac{5}{2}}{100} = \frac{4000 \times 25}{200} = \frac{100000}{200} = 500$$

Nirav's interest is Rs. 500.

Mehul's Interest:

$$SI_2 = \frac{5000 \times 5 \times 2.5}{100} = \frac{5000 \times 5 \times \frac{5}{2}}{100} = \frac{5000 \times 25}{200} = \frac{125000}{200} = 625$$

Mehul's interest is Rs. 625.

Interest Difference:

$$SI_2 - SI_1 = 625 - 500 = 125$$

The difference in interest is Rs. 125, which matches the information given in the question. Thus, the calculated value of x = 5 is correct.

Revision Table: Key Simple Interest Concepts

Term Definition In this Problem
Principal (P) The initial amount of money borrowed or lent. Rs. 4000 (Nirav), Rs. 5000 (Mehul)
Rate (R) The annual interest rate (usually in percent). x% (what we need to find)
Time (T) The duration for which the money is borrowed or lent (in years). 2.5 years
Simple Interest (SI) Interest calculated only on the principal amount. SI₁ (Nirav), SI₂ (Mehul)
SI₂ - SI₁ = 125
Formula $$SI = \frac{P \times R \times T}{100}$$ Used to find SI₁ and SI₂

Additional Information: Simple Interest vs. Compound Interest

It's important to distinguish between simple interest and compound interest.

  • Simple Interest: Interest is calculated only on the original principal amount. The interest earned in previous periods is not added to the principal for calculating the current period's interest. This problem uses simple interest.
  • Compound Interest: Interest is calculated on the principal amount plus any accumulated interest from previous periods. The interest "compounds" over time, leading to a higher total interest amount compared to simple interest over the same period and rate.

The formula for compound interest is different, and problems involving compound interest require a different approach.

Was this answer helpful?

Important Questions from Simple Interest

  1. How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest ?

  2. If the interest on a sum of Rs.1200 is more than the interest on Rs.1000 by Rs.120 in three years, then what is the rate of interest per annum?.

  3. The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?

  4. A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?

  5. P borrowed an amount from Q at a simple interest of 10% p.a. At the end of the year, P paid back Rs 99000 which was 90% of what she owed. How much money did P borrow?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App