The question asks for the principal sum (P) that earns a simple interest (I) of ₹480 over a period (T) of 2 years at an annual interest rate (R) of 16%.
The formula for simple interest is:
\( I = \frac{P \times R \times T}{100} \)
Where:
To find the principal sum (P), we rearrange the formula:
\( P = \frac{I \times 100}{R \times T} \)
Substitute the given values into the rearranged formula:
\( P = \frac{480 \times 100}{16 \times 2} \)
First, calculate the denominator:
\( 16 \times 2 = 32 \)
Now, calculate the numerator:
\( 480 \times 100 = 48000 \)
Finally, divide the numerator by the denominator:
\( P = \frac{48000}{32} \)
\( P = 1500 \)
Therefore, the sum that will earn an interest of ₹480 in 2 years at 16% simple interest is ₹1500.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.