The problem requires finding the initial sum (Principal, P) that yields a specific simple interest (SI) over a given time period (T) at a certain interest rate (R).
The formula for Simple Interest is:
\( SI = \frac{P \times R \times T}{100} \)
Where:
We need to rearrange the formula to solve for P:
\( P = \frac{SI \times 100}{R \times T} \)
Given values are:
Substitute these values into the rearranged formula:
\( P = \frac{480 \times 100}{15 \times 2} \)
The Principal sum required is ₹1600.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
In what duration will a sum of money double itself at 10% per annum rate of simple interest?
Find the simple interest (in ₹) if a sum of ₹400 is borrowed for 5.5 years at 4% per annum rate of interest.