What is the equation of a line having a slope -1/3 and y-intercept equal to 6?
x + 3y = 18
Slope-intercept form: \(y = mx + c\) with \(m = -\tfrac{1}{3}\) and \(c = 6\):
\[y = -\dfrac{x}{3} + 6\]
Multiply through by 3 and rearrange:
\[3y = -x + 18 \implies x + 3y = 18\]
Therefore the equation is x + 3y = 18.
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