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Question

Point A divides segment BC in the ratio 1 : 3. The co-ordinates of B are (4, -4) and that of C are (0, 6). What are the co-ordinates of point A?

This question was previously asked in
SSC CGL 2017 (Tier 1) Previous Year Paper (16-Aug-2017) (Shift 1)
The correct answer is

(3, -1.5)

By the section formula, point A dividing BC internally in ratio \(m:n = 1:3\) has coordinates:

\[A=\left(\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}\right)\]

With \(B(4,-4)\), \(C(0,6)\):

\[A=\left(\frac{1(0)+3(4)}{4},\frac{1(6)+3(-4)}{4}\right)=\left(\frac{12}{4},\frac{-6}{4}\right)=(3,-1.5)\]

Therefore \(A=\mathbf{(3,-1.5)}\).

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