In the given figure ΔABC, if θ = 80°, the measure of each of the other two angles will be:
50°
From the following figure,
In Isosceles triangle ABC
∠ACB = ∠ABC [AC = AB]
Given, ∠BAC = 80°
In ΔABC
∠ACB + ∠ABC + ∠BAC = 180°
⇒ 2∠ACB = 180° - 80° = 100°
⇒ ∠ACB = 100°/2 = 50°Similar Questions
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