In the triangle, if AB = AC and ∠ABC = 72°, then ∠BAC is:
36°
The question asks us to find the measure of angle ∠BAC in a triangle ABC. We are given that two sides, AB and AC, are equal in length, and one angle, ∠ABC, measures 72°.
A triangle with two sides of equal length is called an isosceles triangle. A key property of isosceles triangles is that the angles opposite the equal sides are also equal.
In triangle ABC, we are given that AB = AC.
Since AB = AC, the angles opposite these sides must be equal. Therefore, ∠ACB = ∠ABC.
We are given that ∠ABC = 72°. So, ∠ACB must also be 72°.
Let's summarize the known angles:
| Angle | Measure |
|---|---|
| ∠ABC | $72°$ |
| ∠ACB | $72°$ |
The sum of the interior angles in any triangle is always 180°. For triangle ABC, this means:
$\text{∠BAC} + \text{∠ABC} + \text{∠ACB} = 180°$
Now, substitute the known values for ∠ABC and ∠ACB:
$\text{∠BAC} + 72° + 72° = 180°$
Combine the angles:
$\text{∠BAC} + 144° = 180°$
To find ∠BAC, subtract 144° from 180°:
$\text{∠BAC} = 180° - 144°$
$\text{∠BAC} = 36°$
Based on the properties of isosceles triangles and the angle sum property of triangles, the measure of angle ∠BAC is 36°.
| Concept | Description | Application |
|---|---|---|
| Isosceles Triangle Property | If two sides are equal, angles opposite them are equal. | AB = AC $\implies$ ∠ABC = ∠ACB |
| Triangle Angle Sum Property | Sum of all angles in a triangle is $180°$. | ∠BAC + ∠ABC + ∠ACB = $180°$ |
Triangles can be classified by their sides and angles.
Understanding these classifications helps in solving geometry problems involving triangles.
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