The problem requires finding the next time all four table clocks ring together. They ring at intervals of 10 minutes, 15 minutes, 20 minutes, and 25 minutes. To find when they will ring together again, we need to calculate the Least Common Multiple (LCM) of these intervals.
First, find the prime factorization of each interval:
The LCM is found by taking the highest power of each prime factor present in any factorization:
$ \text{LCM}(10, 15, 20, 25) = 2^2 \times 3^1 \times 5^2 $
$ \text{LCM} = 4 \times 3 \times 25 = 12 \times 25 = 300 \text{ minutes} $
The clocks will ring together every 300 minutes.
Convert 300 minutes into hours:
$ \frac{300 \text{ minutes}}{60 \text{ minutes/hour}} = 5 \text{ hours} $
They all rang together at 10 a.m. They will ring together again after 5 hours.
Adding 5 hours to 10 a.m.:
$10:00 \text{ a.m.} + 5 \text{ hours} = 15:00$
In standard time, 15:00 is 3:00 p.m.
The clocks will ring together again at 3:00 p.m.
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?