The problem requires finding the next time all four table clocks ring together. They ring at intervals of 10 minutes, 15 minutes, 20 minutes, and 25 minutes. To find when they will ring together again, we need to calculate the Least Common Multiple (LCM) of these intervals.
First, find the prime factorization of each interval:
The LCM is found by taking the highest power of each prime factor present in any factorization:
$ \text{LCM}(10, 15, 20, 25) = 2^2 \times 3^1 \times 5^2 $
$ \text{LCM} = 4 \times 3 \times 25 = 12 \times 25 = 300 \text{ minutes} $
The clocks will ring together every 300 minutes.
Convert 300 minutes into hours:
$ \frac{300 \text{ minutes}}{60 \text{ minutes/hour}} = 5 \text{ hours} $
They all rang together at 10 a.m. They will ring together again after 5 hours.
Adding 5 hours to 10 a.m.:
$10:00 \text{ a.m.} + 5 \text{ hours} = 15:00$
In standard time, 15:00 is 3:00 p.m.
The clocks will ring together again at 3:00 p.m.
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Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
The sum of two numbers is 1215 and their HCF is 81. How many such pairs of numbers can be formed?
The LCM of two numbers in 48. Their ratio is 2:3 What is the sum of the numbers?