This solution demonstrates how to find an unknown number when its Highest Common Factor (HCF), Least Common Multiple (LCM), and one of the numbers are provided. We utilize the fundamental relationship between these values.
The product of two numbers is always equal to the product of their HCF and LCM.
Let the two numbers be $N_1$ and $N_2$. The relationship is expressed as:
$ N_1 \times N_2 = \text{HCF} \times \text{LCM} $
We are given:
Substitute the known values into the formula:
$ 48 \times N_2 = 16 \times 240 $
To find $N_2$, we isolate it:
$ N_2 = \frac{16 \times 240}{48} $
Simplify the calculation:
$ N_2 = \frac{16}{48} \times 240 $
Since $\frac{16}{48}$ simplifies to $\frac{1}{3}$:
$ N_2 = \frac{1}{3} \times 240 $
$ N_2 = 80 $
Thus, the other number is 80.
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