To solve this problem, we use the fundamental relationship between two numbers and their Highest Common Factor (H.C.F.) and Least Common Multiple (L.C.M.). The relationship is stated as:
Product of the two numbers = H.C.F. × L.C.M.
Let the two numbers be $Number1$ and $Number2$. We are given:
Using the formula:
$ \text{Number1} \times \text{Number2} = \text{H.C.F.} \times \text{L.C.M.} $
Substitute the given values into the equation:
$ 55 \times \text{Number2} = 5 \times 495 $
First, calculate the product of the H.C.F. and L.C.M.:
$ 5 \times 495 = 2475 $
Now, the equation becomes:
$ 55 \times \text{Number2} = 2475 $
To find $Number2$, divide the product by the known number (55):
$ \text{Number2} = \frac{2475}{55} $
Performing the division:
$ \text{Number2} = 45 $
Therefore, the other number is 45.
What is the LCM of $\sqrt[2]{169}$, $\sqrt[3]{27}$, $\sqrt[3]{64}$ and $\sqrt[2]{144}$ ?
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?