To solve this problem, we use the fundamental relationship between two numbers and their Highest Common Factor (H.C.F.) and Least Common Multiple (L.C.M.). The relationship is stated as:
Product of the two numbers = H.C.F. × L.C.M.
Let the two numbers be $Number1$ and $Number2$. We are given:
Using the formula:
$ \text{Number1} \times \text{Number2} = \text{H.C.F.} \times \text{L.C.M.} $
Substitute the given values into the equation:
$ 55 \times \text{Number2} = 5 \times 495 $
First, calculate the product of the H.C.F. and L.C.M.:
$ 5 \times 495 = 2475 $
Now, the equation becomes:
$ 55 \times \text{Number2} = 2475 $
To find $Number2$, divide the product by the known number (55):
$ \text{Number2} = \frac{2475}{55} $
Performing the division:
$ \text{Number2} = 45 $
Therefore, the other number is 45.
What is the LCM of $\sqrt[2]{169}$, $\sqrt[3]{27}$, $\sqrt[3]{64}$ and $\sqrt[2]{144}$ ?
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
The sum of two numbers is 1215 and their HCF is 81. How many such pairs of numbers can be formed?
The LCM of two numbers in 48. Their ratio is 2:3 What is the sum of the numbers?