This question is built on drawn structures, so the options cannot be reproduced as text. The chemistry it tests is set out below.

Br₂ in CCl₄ is the classic condition for electrophilic addition to an alkene. The solvent matters: carbon tetrachloride is non-polar and non-nucleophilic, so it cannot compete for the intermediate, and the reaction is run in the dark to avoid the radical substitution pathway that light would trigger.

The mechanism has two stages. The alkene π electrons attack bromine, and as the Br-Br bond breaks the resulting cation is not a simple carbocation but a bridged, three-membered bromonium ion. Bromide is expelled in the same step.

The bromide ion then opens that bridge by attacking a carbon from the back face, since the front face is blocked by the bromine already bridging. This enforces anti addition: the two bromine atoms end up on opposite faces of the former double bond.

The stereochemical consequence is what the options usually test. Addition to a cyclic alkene gives the trans-1,2-dibromide, and addition to an acyclic alkene gives a specific pair of enantiomers or a meso compound depending on the substitution pattern — never a mixture of syn and anti products.

The bromonium intermediate also explains why no rearrangement occurs: the positive charge is delocalised over the bridge rather than localised on a single carbon, so hydride and alkyl shifts do not take place.

Per the official final answer key the answer is option (A).