Understanding Displacement Current in Capacitors
Displacement current ($I_d$) is a concept introduced by Maxwell, crucial in understanding electromagnetic waves and circuits containing capacitors. In a capacitor, displacement current flows specifically when the voltage across its plates is changing.
For a parallel plate capacitor with capacitance $C$, the relationship between charge $Q$ and voltage $V$ is $Q = CV$. The displacement current is defined as $I_d = \epsilon_0 \frac{d\Phi_E}{dt}$, where $\Phi_E$ is the electric flux. For a capacitor, this simplifies to the rate of change of charge:
$I_d = \frac{dQ}{dt}$
Substituting $Q = CV$, we get:
$I_d = \frac{d(CV)}{dt} = C \frac{dV}{dt}$
This formula shows that displacement current is directly proportional to the rate at which the voltage ($V$) across the capacitor plates changes over time ($t$).
Based on the formula $I_d = C \frac{dV}{dt}$, displacement current flows whenever the voltage across the capacitor plates is changing. This occurs when the voltage is either increasing or decreasing with time.
Therefore, the conditions under which displacement current flows are when the voltage:
A uniform time-varying magnetic field exists in a circular region of radius $R$, directed perpendicular into the plane of the paper, increasing at a constant rate $\alpha$. A straight conducting rod of length $2R$ is placed exactly along the diameter of the circular region (passing through the centre). Find the induced emf across the rod.

There is a ring of radius $r$ having linear charge density $\lambda$ and rotating with a uniform angular velocity $\omega$. The magnitude of the magnetic field produced by this ring at its own centre would be
($\mu_0 = \text{permeability of air}$)