The starting vector is given as: $\( \vec{v} = 3\hat{i} \)$
This vector initially points along the positive $x$-axis with a magnitude of 3 units.
The rotation follows these conditions:
In the $x-z$ plane, a vector with components $(x, z)$ is transformed to $(x', z')$.
A standard *counter-clockwise* rotation by an angle $\phi$ is given by:
A *clockwise* rotation by angle $\theta$ is equivalent to a *counter-clockwise* rotation by angle $-\theta$. Substituting $\phi = -\theta$ into the formulas:
For the initial vector $\vec{v} = 3\hat{i}$, the components are $x=3$ and $z=0$. Applying the clockwise rotation formulas:
This yields the vector \( 3\cos\theta\hat{i} - 3\sin\theta\hat{k} \). This outcome differs from the options provided.
Given the options, let's reconsider the interpretation. Option D ($3\cos\theta\hat{i} + 3\sin\theta\hat{k}$) corresponds to a standard *counter-clockwise* rotation by angle $\theta$ in the $x-z$ plane.
Assuming the rotation results in the form presented in the options, we apply the standard counter-clockwise rotation formula with $\phi = \theta$ to the initial components ($x=3, z=0$):
The final vector $\vec{v}'$ is therefore:
$\( \vec{v}' = 3\cos\theta\hat{i} + 3\sin\theta\hat{k} \)$
The calculated vector \( 3\cos\theta\hat{i} + 3\sin\theta\hat{k} \) matches Option D.