The base of a triangle is half the base of a parallelogram having the same area as that of the triangle. The ratio of the heights of the triangle to the parallelogram will be:
4 : 1
Let the base of parallelogram = b
⇒ Base of triangle = b/2
Let the height of parallelogram be h 1and height of triangle be h 2
Given that the area of parallelogram is equal to area of triangle
⇒ 1/2 × b/2 × h 2= b × h 1
∴ h 2∶ h 1= 4 ∶ 1From each corner of a square with an edge of 4 cm, a 1 cm segment was chopped off from each side containing a vertex. What is the perimeter and the area of the octagon thus created?
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