The question asks for the volume of water flowing into the sea per minute. We can calculate this by finding the volume of a rectangular prism of water that passes a point in one minute. The dimensions of this prism are the river's width, depth, and the distance the water travels in one minute.
To calculate the volume in cubic meters per minute, we need the speed in meters per minute.
The cross-sectional area ($A$) is the product of the river's depth and width.
The volume of water flowing per minute ($V_{min}$) is the cross-sectional area multiplied by the distance the water travels in one minute (which is the speed in m/min).
Therefore, the quantity of water that runs into the sea per minute is $4500$ m$^3$. This matches Option A.
A regular hexagonal garden with each side measuring 14 metres is surrounded by a circular jogging track that has a radius of 21 metres from the centre of the hexagon. Find the sum of the perimeters of both shapes.
(Use $\pi = \frac{22}{7}$)
What is the area of this parallelogram in sq.cm.? The measurements are in cms.
