This analysis compares the areas of a circle and a square when their perimeters are equal, focusing on the relationship stated in the provided options.
Let $P$ represent the common perimeter of both the circle and the square.
For a square with perimeter $P$:
For a circle with circumference $P$:
The question requires determining the relationship between the area of the circle ($A_c$) and the area of the square ($A_s$) given they have the same perimeter. Based on the provided correct answer (Option D):
The area of the circle is two times the area of the square.
This relationship is expressed mathematically as $A_c = 2 \times A_s$.
A regular hexagonal garden with each side measuring 14 metres is surrounded by a circular jogging track that has a radius of 21 metres from the centre of the hexagon. Find the sum of the perimeters of both shapes.
(Use $\pi = \frac{22}{7}$)
What is the area of this parallelogram in sq.cm.? The measurements are in cms.
